Females

Puzzle:

• A is the father of two children - B and D who are of different sexes.
• C is B's spouse.
• E is the same sex as D.
• B and C have the two children - F who is the same sex as B and G who is the same sex as C.
• E's mother, H who is married to L, is the sister of D's mother, M.
• E and E's spouse, I have two children - J and K who are the same sex as I.
  

Note that no persons have married more than once. Also, there are more number of females than males. Can you tell how many females are there?

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Solution:

There are 7 females and 6 males.

Assume that there are four sexes - male, female, X and Y.

L(m) H(f) M(f) A(m) E(x) I(y) D(x) B(y) C(x) J(y) K(y) F(y) G(x)

It is clear that there are altogether 13 persons - 2 males, 2 females, 4 Xs and 5 Ys. It is given that there are more number of females than male. Hence, all Y must represent female. Thus, there are 7 females and 6 males.

The Party

Yesterday in a party, I asked Mr. Shah his birthday. With a mischievous glint in his eyes he replied. "The day before yesterday I was 83 years old and next year I will be 86." Can you figure out what is the Date of Birth of Mr. Shah? Assume that the current year is 2000.

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Solution:

Mr. Shah's date of birth is 31 December, 1915

Today is 1 January, 2000. The day before yesterday was 30 December, 1999 and Mr. Shah was 83 on that day. Today i.e. 1 January, 2000 - he is 84. On 31 December 2000, he will be 85 and next year i.e. 31 December, 2001 - he will be 86. Hence, the date of birth is 31 December, 1915. Many people do think of Leap year and date of birth as 29th February as 2000 is the Leap year and there is difference of 3 years in Mr. Shah's age. But that is not the answer.

Find the next three number

Puzzle:

Find next three numbers in the given series...

                 1 2 3 2 1 2 3 4 2 1 2 3 4 3 2 ? ? ?

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Solution:

The next three numbers are 3, 4 and 5.

The pattern is - the number of letters in the Roman numeral representation of the numbers i.e. number of letters in I, II, III, IV, V, VI, VII, VIII, IX, X, XI, XII, XIII, XIV, XV, ..... Hence, the next numbers in the given series are 3(XVI), 4(XVII), 5(XVIII), 3(XIX), 2(XX), 3(XXI), 4(XXII), 5(XXIII), 4(XXIV), 3(XXV), etc...